1/b^2-7b+10+1/b-2=2/b^2-7b+10

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Solution for 1/b^2-7b+10+1/b-2=2/b^2-7b+10 equation: 



1/b^2-7b+10+1/b-2=2/b^2-7b+10

We move all terms to the left:

1/b^2-7b+10+1/b-2-(2/b^2-7b+10)=0



Domain of the equation: b^2!=0

b^2!=0/

b^2!=√0

b!=0

b∈R





Domain of the equation: b!=0

b∈R





Domain of the equation: b^2-7b+10)!=0

b∈R



We add all the numbers together, and all the variables

-7b+1/b^2+1/b-(2/b^2-7b+10)+8=0

We get rid of parentheses

-7b+1/b^2+1/b-2/b^2+7b-10+8=0

We calculate fractions

We do not support ebpression: b^3

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